x^2+26x-41.25=0

Solution for x^2+26x-41.25=0 equation:

x^2+26x-41.25=0

a = 1; b = 26; c = -41.25;
Δ = b2-4ac
Δ = 262-4·1·(-41.25)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-29}{2*1}=\frac{-55}{2}
=-27+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+29}{2*1}=\frac{3}{2}
=1+1/2
$